Python Programming

ChineseGuy · 03-30-2008, 11:24 PM

anyone here knows how to do python?

I'm trying to do this simple fuction

input: num1 + num = results

but i want the output be in pictures, so i decided to split num1 and num2 into digits by itself, so that i can apply the picture files to represent each number.

now the problem is, after i split them into single digits, i can't get rid of the zero on the left side.

ex. 01 + 01 = 2 ( i only split num1 and num2, so the results won't show 02)

and, do i need to split results into single digits too? I believe doing that to the results would make the situation alot more messy....

help is appreciated

thanks,

bastula · 03-31-2008, 12:42 AM

Can you post some of your code so I can see what you mean? Are you trying to split the number using string parsing? How do you want to represent the output in pictures?

twinturbodude · 03-31-2008, 12:46 AM

Quote:

Originally Posted by ChineseGuy

anyone here knows how to do python?

I'm trying to do this simple fuction

input: num1 + num = results

but i want the output be in pictures, so i decided to split num1 and num2 into digits by itself, so that i can apply the picture files to represent each number.

now the problem is, after i split them into single digits, i can't get rid of the zero on the left side.

ex. 01 + 01 = 2 ( i only split num1 and num2, so the results won't show 02)

and, do i need to split results into single digits too? I believe doing that to the results would make the situation alot more messy....

help is appreciated

thanks,

Sounds like you may be having an issue with strings vs. integers. Python differentiates between "02" which is a string consisting of two characters, "0" and "2", and 2, which is an integer. The + operator does string concatenation if you are trying to add strings, numeric addition if you are trying to add numbers, and gives a runtime error if you attempt to add a string and a number. Like:

$ python
Python 2.4.3 (#1, Jul 4 2006, 23:58:18)
[GCC 4.0.2 20050901 (prerelease) (SUSE Linux)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> "02" + "02"
'0202'
>>> 2 + 2
4
>>> "02" + 2
Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: cannot concatenate 'str' and 'int' objects
>>>

So, you may need to convert things to and from strings and integers. To go from string -> int use the builtin int() function, and to go from int to string you can use something like "%s" % 2 (or just put the integer or var in backticks also works).

ChineseGuy · 03-31-2008, 01:01 AM

i'm very noob with python, so my codes might look weird

import cgi
form = cgi.FieldStorage()

zero = open ( "0.jpg" )
one = open ( "1.jpg" )
two = open ( "2.jpg" )
three = open ( "3.jpg" )
four = open ( "4.jpg" )
five = open ( "5.jpg" )
six = open ( "6.jpg" )
seven = open ( "7.jpg" )
eight = open ( "8.jpg" )
nine = open ( "9.jpg" )
num1 = int( form["num1"].value )
num2 = int( form["num2"].value )
op = form["op"].value
first_digit = num1 / 10
second_digit = num1 - (10*first_digit)
secondfirst_digit = num2 / 10
secondsecond_digit = num2 - (10*secondfirst_digit)

print """Content-type: text/html

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html><head>
<title>Assignment 2</title>
</head><body>
"""
if num1 > 99 or num1 < 0 or num2 > 99 or num2 < 0 :
print "Error: Wrong number."

else:
if op == "+" :
print "%s%s + %s%s = %s" % (first_digit, second_digit, secondfirst_digit, secondsecond_digit, num1 + num2)

if op == "-" :
print "%s%s - %s%s = %s" % (first_digit, second_digit, secondfirst_digit, secondsecond_digit, num1 - num2)

if op == "*" :
print "%s%s * %s%s = %s" % (first_digit, second_digit, secondfirst_digit, secondsecond_digit, num1 * num2)

if op == "/" and num2 != 0 :
print "%s%s / %s%s = %s" % (first_digit, second_digit, secondfirst_digit, secondsecond_digit, num1 / num2)

if op == "/" and num2 == 0:
print "Error: Undefined."

if op == "+" and first_digit == 0 :
num1 = second_digit
if op == "+" and secondsecond_digit == 0 :
num2 = secondsecond_digit

if op == "-" and first_digit == 0 :
num1 = second_digit
if op == "-" and secondsecond_digit == 0 :
num2 = secondsecond_digit

if op == "*" and first_digit == 0 :
num1 = second_digit
if op == "*" and secondsecond_digit == 0 :
num2 = secondsecond_digit

if op == "/" and first_digit == 0 :
num1 = second_digit
if op == "/" and secondsecond_digit == 0 :
num2 = secondsecond_digit

print "</body></html>"

dont' mind the indentations, copy and paste doesn't copy indents too i guess

ChineseGuy · 03-31-2008, 01:08 AM

Quote:

Originally Posted by twinturbodude

Sounds like you may be having an issue with strings vs. integers.

i'm not sure if it's strings vs integers problem, looks correct to me

but please check out my codes and see if that's the problem

i've been stuck on this part for hours already

TheLegacy · 03-31-2008, 04:27 PM

python man or man I haven't used that for awhillleee. Only used python for PERL

ChineseGuy · 03-31-2008, 08:22 PM

anyone?

twinturbodude · 04-02-2008, 01:14 AM

Ok, think I understand what you're trying to do. You probably don't want to open the actual files, but instead just put an html image tage, like

<img src="1.jpg">

...in the output. Your logic with the division by 10 to get the first digit and then subtracting that off will work, but only if the data coming back from the cgi form (like form["num1"].value) is in numeric form...I'd expect it to actually be string data that comes back. If that's the case, then it's much easier to just do:

first_digit = form["num1"].value[0]
second_digit= form["num1"].value[1]

...since strings can be treated like lists. Then you could just do

print '<img src="%s.jpg">' % first_digit
print '<img src="%s.jpg">' % second_digit

...to output the first number's images (and do the second number similarly). Does this make any sense? : )

ChineseGuy · 04-02-2008, 01:31 AM

Quote:

Originally Posted by twinturbodude

Ok, think I understand what you're trying to do. You probably don't want to open the actual files, but instead just put an html image tage, like

<img src="1.jpg">

...in the output. Your logic with the division by 10 to get the first digit and then subtracting that off will work, but only if the data coming back from the cgi form (like form["num1"].value) is in numeric form...I'd expect it to actually be string data that comes back. If that's the case, then it's much easier to just do:

first_digit = form["num1"].value[0]
second_digit= form["num1"].value[1]

...since strings can be treated like lists. Then you could just do

print '<img src="%s.jpg">' % first_digit
print '<img src="%s.jpg">' % second_digit

...to output the first number's images (and do the second number similarly). Does this make any sense? : )

i think i get it, but i'll need to try it out first

btw, i have a HTM file linked to this python, so do i still need to do <> for hte img src?

one more problem, i want to get rid of the zero on the first_digit ...'cause the equation comes out like 01+01 = 2, and i want to make it to 1 + 1 = 2

twinturbodude · 04-02-2008, 02:49 PM

Assuming again that the form data comes across as a string (I still haven't checked this but think it's true) you can just
do a regex to strip off the leading 0, like:

>>> import re
>>>
>>> teststr = '02'
>>> teststr = re.sub(r'^0', '', teststr)
>>> print teststr
2

I'm not sure offhand if you need the <>'s or not in your system. Try it both ways and see which works.

03-30-2008, 11:24 PM	#1
ChineseGuy QuickShifter 145 Rep 1,499 Posts Drives: Black E90 Join Date: Nov 2005 Location: North Pole iTrader: (2)	Python Programming anyone here knows how to do python? I'm trying to do this simple fuction input: num1 + num = results but i want the output be in pictures, so i decided to split num1 and num2 into digits by itself, so that i can apply the picture files to represent each number. now the problem is, after i split them into single digits, i can't get rid of the zero on the left side. ex. 01 + 01 = 2 ( i only split num1 and num2, so the results won't show 02) and, do i need to split results into single digits too? I believe doing that to the results would make the situation alot more messy.... help is appreciated thanks,
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03-31-2008, 12:42 AM	#2
bastula Second Lieutenant 183 Rep 266 Posts Drives: 2019 M550i xDrive Join Date: Sep 2005 Location: Chicago iTrader: (1) Garage List 2022 BMW X7 [0.00] 2019 BMW M550i xDrive [0.00]	Can you post some of your code so I can see what you mean? Are you trying to split the number using string parsing? How do you want to represent the output in pictures? __________________ M550i xDrive Mediterranean Blue with Ivory White Nappa, Gray Poplar, Driving Assistance Plus, Premium, Exec, Parking Assistance, Heated Steering, Front+Rear Heated Seats, 20" Individual V-Spoke wheels 759i, 19" Style 786M winter wheels, Euro Amber Rear Turn Signals 335i Coupe - Retired
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03-31-2008, 01:01 AM	#4
ChineseGuy QuickShifter 145 Rep 1,499 Posts Drives: Black E90 Join Date: Nov 2005 Location: North Pole iTrader: (2)	i'm very noob with python, so my codes might look weird import cgi form = cgi.FieldStorage() zero = open ( "0.jpg" ) one = open ( "1.jpg" ) two = open ( "2.jpg" ) three = open ( "3.jpg" ) four = open ( "4.jpg" ) five = open ( "5.jpg" ) six = open ( "6.jpg" ) seven = open ( "7.jpg" ) eight = open ( "8.jpg" ) nine = open ( "9.jpg" ) num1 = int( form["num1"].value ) num2 = int( form["num2"].value ) op = form["op"].value first_digit = num1 / 10 second_digit = num1 - (10first_digit) secondfirst_digit = num2 / 10 secondsecond_digit = num2 - (10secondfirst_digit) print """Content-type: text/html <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html><head> <title>Assignment 2</title> </head><body> """ if num1 > 99 or num1 < 0 or num2 > 99 or num2 < 0 : print "Error: Wrong number." else: if op == "+" : print "%s%s + %s%s = %s" % (first_digit, second_digit, secondfirst_digit, secondsecond_digit, num1 + num2) if op == "-" : print "%s%s - %s%s = %s" % (first_digit, second_digit, secondfirst_digit, secondsecond_digit, num1 - num2) if op == "" : print "%s%s %s%s = %s" % (first_digit, second_digit, secondfirst_digit, secondsecond_digit, num1 * num2) if op == "/" and num2 != 0 : print "%s%s / %s%s = %s" % (first_digit, second_digit, secondfirst_digit, secondsecond_digit, num1 / num2) if op == "/" and num2 == 0: print "Error: Undefined." if op == "+" and first_digit == 0 : num1 = second_digit if op == "+" and secondsecond_digit == 0 : num2 = secondsecond_digit if op == "-" and first_digit == 0 : num1 = second_digit if op == "-" and secondsecond_digit == 0 : num2 = secondsecond_digit if op == "" and first_digit == 0 : num1 = second_digit if op == "" and secondsecond_digit == 0 : num2 = secondsecond_digit if op == "/" and first_digit == 0 : num1 = second_digit if op == "/" and secondsecond_digit == 0 : num2 = secondsecond_digit print "</body></html>" dont' mind the indentations, copy and paste doesn't copy indents too i guess
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03-31-2008, 04:27 PM	#6
TheLegacy Gangsta status 78 Rep 973 Posts Drives: 2002 E39 M5, heavily modded Join Date: May 2007 Location: Shibuya Tokyo, Rockland NY, Killeen TX iTrader: (0)	python man or man I haven't used that for awhillleee. Only used python for PERL __________________ -TheLegacy JDM-EDM-TT-V8-GANGSTA ALL THE WAY Modded "Ready for the Apocalypse"
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03-31-2008, 08:22 PM	#7
ChineseGuy QuickShifter 145 Rep 1,499 Posts Drives: Black E90 Join Date: Nov 2005 Location: North Pole iTrader: (2)	anyone?
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04-02-2008, 01:14 AM	#8
twinturbodude Member 4 Rep 47 Posts Drives: 335xi Join Date: Jun 2007 Location: MA iTrader: (0)	Ok, think I understand what you're trying to do. You probably don't want to open the actual files, but instead just put an html image tage, like <img src="1.jpg"> ...in the output. Your logic with the division by 10 to get the first digit and then subtracting that off will work, but only if the data coming back from the cgi form (like form["num1"].value) is in numeric form...I'd expect it to actually be string data that comes back. If that's the case, then it's much easier to just do: first_digit = form["num1"].value[0] second_digit= form["num1"].value[1] ...since strings can be treated like lists. Then you could just do print '<img src="%s.jpg">' % first_digit print '<img src="%s.jpg">' % second_digit ...to output the first number's images (and do the second number similarly). Does this make any sense? : ) __________________ e90 335xi / 6MT / titanium silver / black leather / premium / cold weather / sport / iPod
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04-02-2008, 02:49 PM	#10
twinturbodude Member 4 Rep 47 Posts Drives: 335xi Join Date: Jun 2007 Location: MA iTrader: (0)	Assuming again that the form data comes across as a string (I still haven't checked this but think it's true) you can just do a regex to strip off the leading 0, like: >>> import re >>> >>> teststr = '02' >>> teststr = re.sub(r'^0', '', teststr) >>> print teststr 2 I'm not sure offhand if you need the <>'s or not in your system. Try it both ways and see which works. __________________ e90 335xi / 6MT / titanium silver / black leather / premium / cold weather / sport / iPod
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